SSC CGL 4 06 2019 Shift 1 Paper

Question : 64 of 100

Marks: +1, -0

x+y+z=19, x^{2}+y^{2}+z^{2}=133

and

x z=y^{2},

then the difference between z and x is

Solution:

(x+y+z)^{2}=x^{2}+y^{2}+z^{2}+2 x y

+2 y z+2 z x

(19)^{2}=133+2\ (x y+y z+y^{2}\ )

361=133+2[y(x+y+z)]

114=[y(19)]

y=6

x z=36

x+z=13

let,

z=9 . x=4

z-x=5

Go to Question:

Prev Question

Next Question