SSC CGL 4 06 2019 Shift 1 Paper

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Question : 66 of 100

Marks: +1, -0

In a circle of radius 10 cm, with centre 0, PQ and PR are two chords each of length 12 cm. PO intersects chord QR at the points S. The length of OS is

2.8 cm
2.5 cm
3.2 cm
3 cm

Solution:

let

0 S=x, P O=10 \ {\cm}

(radius)

P S=10-x

R=\ {a b c}/{4 \Δ}

=10=\ {12 \×12 \×Q R}/{4 \×\ {1}/{2} \×Q R \ ×P S}

5 \×P S=36

5 \×(10-x)=36

50-5 x=36

5 x=14

x=2.8

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