SSC CGL 4 Sep 2016 Paper

Question : 67 of 100

Marks: +1, -0

There are two equal circles of radius 3 cm each and distance between their centres is 10 cm. The length of one of their transverse common tangents is

Solution:

Transverse common tangent
=

√{d^2-(r_1+r_2)^2}

√{10^2-(3+3)^2}

[

r_1

r_2

= 3 cm]
=

√{100-36}

√{64}

= 8 cm

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