If(8 x^{3}-27 y^{3} ) \\div(2 x-3 y) = (A x^{2}+B x y+C y^{2} ) then the value of (2 A+B-C) is :

SSC CGL 6 06 2019 Shift 2 Paper

Question : 60 of 100

Marks: +1, -0

(8 x^{3}-27 y^{3}\ ) \÷(2 x-3 y)

=\ (A x^{2}+B x y+C y^{2}\ )

then the value of

(2 A+B-C)

is :

Solution:

\ {(2 x)^{3}-(3 y)^{3}}/{(2 x-3 y)}=A x^{2}+B x y+C y^{2}

4 x^{2}+9 y^{2}+6 x y=A x^{2}+B x y+C y^{2}

Comparing both sides

A=4, \;\ B=6, \;\; C=9

=(8+6-9)=5

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