SSC CGL 6 06 2019 Shift 2 Paper

Question : 63 of 100

Marks: +1, -0

ABCD is a cyclic quadrilateral whose diagonals intersect at P. If AB=BC, ∠DBC = 70° and ∠BAC = 30°, then the measure of ∠PCD is:

Solution:

A B=B C

Then

\∠ {ACB}=\∠\ {BAC}

\∠\ {BCA}=30°

\ln \Δ {\ABC}

\∠\ {ABP}=50°(\∵\ {A}+\ {B}+\ {C}=180)

\∠ \ {ACD}=\ ∠\ {ABD}=50°

(angles on same chord)

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