SSC CGL 6 06 2019 Shift 2 Paper

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Question : 69 of 100

Marks: +1, -0

If

x=a+\ {1}/{a}

and

y=a-\ {1}/{a}

then

\√{x^{4}+y^{4}-2 x^{2} y^{2}}

is equal to:

$16a^2$
8
$8/a^2$
4

Solution:

\√{\ (x^{2}-y^{2}\ )^{2}}

=x^{2}-y^{2}

=a^{2}+\ {1}/{a^{2}}+2-a^{2}-\ {1}/{a^{2}}+2

=4

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