SSC CGL 7 06 2019 Shift 1 Paper

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Question : 64 of 100

Marks: +1, -0

The value of

\sin ^{2} 30° \cos ^{2} 45°+4 \tan ^{2} 30°+

\ {1}/{2} \sin ^{2} 90°+2 \cos 90°

is:

$15/8$
$47/24$
$23/12$
2

Solution:

\sin ^{2} 30° \cos ^{2} 45°+4 \tan ^{2} 30°+

\ {1}/{2} \sin ^{2} 90°+2 \cos 90°

\⇒\ {1}/{4} \× \ {1}/{2}+4 \× \ {1}/{3}+\ {1}/{2}

\× 1+2 \× 0

\⇒\ {1}/{8}+\ {4}/{3}+\ {1}/{2}

=\ {3+32+12}/{24}=\ {47}/{24}

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