SSC CGL 9 Aug 2015 Shift 2 Paper

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Question : 130 of 200

Marks: +1, -0

If

x/y

=

3/4

, the ratio of (2x + 3y) and (3y – 2x) is

2 : 1
3 : 2
1 : 1
3 : 1

Solution:

x/y

=

3/4

(Given)
∴

{2x+3y}/{3y-2x}

=

{2x/y+{3y}/y}/{{3y}/y-{2x}/y}

(Dividing numerator and denominator by y)
=

{2. x/y+3}/{3-2 . x/y}

=

{2× 3/4 + 3}/{3-2×3/4}

=

{3/2+3}/{3-3/2}

=

{3+6}/{6-3}

=

9/3

= 3 : 1

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