SSC CGL Model Paper 9

Question : 63 of 100

Marks: +1, -0

If tanθ = a, Then value of sin2θ is-

Solution:

tanθ = a
sin2θ = 2sinθ cosθ

2×a/{√a^2+1}×1/ √{a^2+1}={2a}/{a^2+1}

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