If x−\frac{3}{x} = 6,\:x \neq 0, then the value of {x^{4}−{27}/{x^{2}}}/{x^{2}−3x−3} is:

SSC CGL Tier II Quant 18 Nov 2020 Paper

Question : 53 of 100

Marks: +1, -0

x−\;{3}/{x} = 6,\:x ≠ 0,

then the value of

\;{x^{4}−{27}/{x^{2}}}/{x^{2}−3x−3}

is:

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