SSC CHSL 10 Jan 2017 Shift 2 Paper

Coordinates of centroid of triangle with vertices $\left({\mathit{x}}_1,{\mathit{y}}_1\right),\left({\mathit{x}}_2,{\mathit{y}}_2\right)$ and $\left({\mathit{x}}_3,{\mathit{y}}_3\right)$ is $\left(\frac{{\mathit{x}}_1+{\mathit{x}}_2+{\mathit{x}}_3}{3},\frac{{\mathit{y}}_1+{\mathit{x}}_2+{\mathit{y}}_3}{3}\right)$
Let coordinates of centroid G = $\left(\mathit{x},\mathit{y}\right)$
Vertex A(-2,5) and Vertex B(4,4) and C = (7,-3)
⇒ $\mathit{x}=\frac{-2+4+7}{3}$
⇒ $\mathit{X}=\frac{9}{3}=3$
Similarly,⇒ $\mathit{y}=\frac{5+4-3}{3}$
⇒ $\mathit{y}=\frac{6}{3}=2$
∴ Coordinates of centroid G = (3,2)