SSC CHSL 12 Oct 2020 Shift 1 Paper

Question : 55 of 100

Marks: +1, -0

Richa travels from A to B at the speed of

15 {\km} \/ {\h}

, from B to C at

20{\km} \/ {\h}

and from C to D at

30 {\km} \/ {\h}

. If

\AB=\BC=\CD

, then find the Richa's average speed.

Solution:

x=15 {\km} \/ {\h}, y=20 {\km} \/ {\h}

z=30 {\km} \/ {\h}

We know that, if distance travelled is same, then
Average speed

={3 x y z}/{x y+y z+z x}

={3 \×15 \×20 \×30}/{15 \×20+20 \×30+30 \×15}

={27000}/{300+600+450}

={27000}/{1350}=20{\km} \/ {\h}

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