SSC CHSL 12 Oct 2020 Shift 1 Paper

Question : 70 of 100

Marks: +1, -0

\cot \A=k

, then

\sin \A

is equal to (presume that A is an acute angle)

Solution:

\cot \A=k

We know that,

{\cosec}^{2} \A=1+\cot ^{2} \A

{\cosec}^{2} \A=1+k^{2}

{\cosec} \A=\√{1+k^{2}}

\sin \A={1}/{\√{1+k^{2}}}

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