Find the value of \frac{\tan 60^\circ-\tan 15^\circ}{1+\tan 60^\circ \tan 15^\circ}

SSC CHSL 12 Oct 2020 Shift 2 Paper

Question : 59 of 100

Marks: +1, -0

Find the value of

{\tan 60°-\tan 15°}/{1+\tan 60° \tan 15°}

Solution:

{\tan 60°-\tan 15°}/{1+\tan 60° \tan 15°}==\tan (60°-15°)

[\∵\tan (\A-\B)={\tan \A-\tan \B}/{1+\tan \A \tan \B}]

=\tan 45°=1

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