SSC CHSL 12 Oct 2020 Shift 2 Paper

Question : 64 of 100

Marks: +1, -0

In the figure, L is the centre of the circle and ML is the perpendicular to LN. If the area of the

\Δ\MLN

is 36 , then the area of the circle is

Solution:

We know that, area of triangle

={1}/{2} \×

base

\×

height
Then, ar

\Δ \MLN={1}/{2} \×r \×r

36={r^{2}}/{2}

r^{2}=72

Now, area of circle

=\πr^{2}

=\π\×72=72 \π{\cm}^{2}

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