SSC CHSL 17 Mar 2020 Shift 2 Paper

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Question : 72 of 100

Marks: +1, -0

If

{\cosec} \A={25}/{7}

, then what is the value of

\tan \A

?

${7}/{24}$
${25}{24}$
${7}/{25}$
${24}/{25}$

Solution:

{\cosec} \A={25}/{7}

...(i)
We know that,
⇒

{\cosec}^{2} \A-1=\cot ^{2} \A

⇒

({25}/{7})^{2}-1=\cot ^{2} \A

[from Eq. (i)]
⇒

{625}/{49}-1=\cot ^{2} \A

⇒

{625-49}/{49}=\cot ^{2} \A

⇒

{576}/{49}=\cot ^{2} \A

⇒

\cot \A={24}/{7}

⇒

\tan \A={7}/{24}

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