SSC CHSL 17 Mar 2020 Shift 3 Paper

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Question : 64 of 100

Marks: +1, -0

What is the equation of a circle with centre of origin and radius is

6 {\cm}

?

$x^{2}+y^{2}-x-y=36$
$x^{2}+y^{2}-x=36$
$x^{2}+y^{2}-y=36$
$x^{2}+y^{2}-36=0$

Solution:

We know that, equation of a circle is

(x-h)^{2}+(y-k)^{2}=r^{2}

where center is

(h, k)

and radius is

r

.
Now

, h=0, k=0

and

r=6

Hence, the required equation is

(x-0)^{2}+(y-0)^{2}=6^{2}

x^{2}+y^{2}=36

x^{2}+y^{2}-36=0

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