SSC CHSL 19 Mar 2020 Shift 1 Paper

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Question : 69 of 100

Marks: +1, -0

If

\sin x={3}/{5}, 0° \≤x \≤90°

, then the value of

\cot x \.\sec x

is

${3}/{5}$
${5}/{3}$
${4}/{5}$
${3}/{4}$

Solution:

Given,

\sin x={3}/{5}, 0° \≤x \≤90°

The value of

\cot x \×\sec x={\cos x}/{\sin x} \×{1}/{\cos x}

={1}/{\sin x}={1}/{3 / 5}={5}/{3}

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