SSC CHSL 19 Mar 2020 Shift 1 Paper

Question : 75 of 100

Marks: +1, -0

A pair of tangents AB and AC are drawn from a point which is at a distance of

10 {\cm}

from the centre O of a circle of radius

6 {\cm}

, then the area (in

{\cm}^{2}

) of quadrilateral ABOC is

Solution:

Given,

\∠\OBA=90°

∴ In

\Δ\BOA

⇒

\BA^{2}=\OA^{2}\OB^{2}=(10)^{2}-(6)^{2}

⇒

\BA^{2}=100-36=64

⇒

\BA=\√{64}=8 {\cm}

∴ Area of quadrilateral ABOC

=2 \×

Area of

\Δ{\AOB}

=2 \×{1}/{2} \×\OB \×\AB

=2 \×{1}/{2} \×8 \×6=48 {\cm}^{2}

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