SSC CHSL 19 Mar 2020 Shift 3 Paper

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Question : 62 of 100

Marks: +1, -0

Mohan finishes a journey by scooter in

5 {\h}

. He travels the first half of the journey at

30 {\km} \/ {\h}

and the second half of the journey at

20 {\km} \/ {\h}

. The distance covered by him is

$140 {\km}$
$100 {\km}$
$120 {\km}$
$130{\km}$

Solution:

Let the distance covered by Mohan be

x {\km}

.
∴ According to the question,

{x}/{60}+{x}/{40}=5

\⇒{2 x+3 x}/{120}=5

⇒

d={120}/{5} \×5=120 {\km}

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