SSC CHSL 20 Dec 2015 Shift 2 Paper

Question : 101 of 200

Marks: +1, -0

The angle of elevation of the Sun when the length of the shadow of a pole is equal to its height, is

Solution:

Height of pole AB = Length of shadow BC = x
In ∆ABC,
⇒

tan(∠ ACB) ={AB} /{BC}

⇒

tanθ = x/x

⇒

tanθ = x

⇒

θ = tan^{−1}(1) = 45 ∘

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