SSC CHSL 20 Dec 2015 Shift 2 Paper

Question : 112 of 200

Marks: +1, -0

A man walks a certain distance in certain time, if he had gone 3 km an hour faster, he would have taken 1 hour less than the schedule time. If he had gone 2 km an hour slower, he would have been one hour longer on the road. The distance (in km) is

Validate

Solution:

Let ideal speed of man = s km/hr and ideal time = t hours
⇒ Distance =

d=st

----(i)
According to ques, ⇒

d = (s + 3)(t − 1)

⇒

d = st − s + 3t − 3

Thus, using equation (i), ⇒

3t-s=3

-----(ii)
Also,

d = (s − 2)(t + 1)

⇒

d = st + s − 2t − 2

⇒

-2t+s=2

---(iii)
Adding equations (ii) and (iii), we get :
⇒

3t − 2t = 3 + 2

⇒

t = 5

Substituting above value in equation (ii), ⇒

s = 3(5) − 3 = 15 − 3 = 12

∴ Distence =

12×5=60

Go to Question:

Prev Question

Next Question