SSC CHSL 20 Dec 2015 Shift 2 Paper

Question : 122 of 200

Marks: +1, -0

A is a point on the x-axis with abscissa - 8 and B is the pint on the y-axis with ordinate 15. The length of AB is

Solution:

Now, OA = 8 units and OB = 15 units
⇒

(AB)^2 = (OA)^ 2 + (OB)^2

⇒

(AB) ^2 = (8)^ 2 + (15)^ 2

⇒

(AB) ^2 = 64 + 225 = 289

⇒

AB = √289=17

units

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