SSC CHSL 6 Dec 2015 Shift 1 Paper

Let the amount deposited in bank = Rs. 100x and in post office = Rs. $\left(3,00,000-100\mathit{x}\right)$
Time period = $\frac{1}{12}$ years
Simple interest = $\frac{\mathit{P}\times \mathit{R}\times \mathit{T}}{100}$
According to ques,
⇒ $\left(\frac{100\mathit{x}\times 6\times 1}{12\times 100}\right)$ $+\left(\frac{\left(3,00,000-100\mathit{x}\right)\times 10\times 1}{12\times 100}\right)$= 2000
⇒ $\left(\frac{\mathit{x}}{2}\right)+\left(2500-\frac{5\mathit{x}}{6}\right)$ = 2000
⇒ $\frac{5\mathit{x}}{2}-\frac{\mathit{x}}{2}=2500-2000$
⇒ $\frac{\mathit{x}}{3}=500$
⇒ $\mathit{x}=500\times 3=1500$
Thus, amount deposited in bank = 100 × 1500 = Rs. 1, 50, 000
Amount deposited in post office = 3, 00, 000 − 1, 50, 000 = Rs. 1, 50, 000
∴ Difference of his deposits in the post office and in the bank = 0