SSC CHSL 6 Dec 2015 Shift 1 Paper
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Question : 133 of 200
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AB is a diameter of a circle having centre at O, PQ is a chord which does not intersect AB. Join AP and BQ.
If ∠BAP = ∠ABQ, then ABQP is a:
If ∠BAP = ∠ABQ, then ABQP is a:
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