SSC CHSL 6 Dec 2015 Shift 2 Paper

Length of train = 156 m and time taken = 30 seconds
⇒ Speed of first train = $\frac{156}{30}=5.2$ m/s
Let speed of second train (length = 156 m) = m/s
According to ques, ⇒ $\left(\mathit{x}+5.2\right)=\frac{156+156}{10}$
⇒ $\left(\mathit{x}+5.2\right)=31.2$
⇒ $\mathit{x}=31.2-5.2=26$ m/s
∴ Speed of second train = $26\times \left(\frac{18}{5}\right)=93.6$ km/hr