SSC CHSL 7 Jan 2017 Shift 3 Paper

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Question : 67 of 100

Marks: +1, -0

If

xy=-30

and

x^2+y^2=61

then find the value of (x + y).

2
3
1
4

Solution:

Given :

x^2+y^2=61

and

xy=-30

Using

{(x+y)^2}=x^2+y^2+2xy

⇒

{(x+y)^2}=61+(2×-30)

⇒

(x+y)=√{61-60}=1

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