SSC CHSL 8 Jan 2017 Shift 3 Paper

Question : 57 of 100

Marks: +1, -0

A solid copper sphere of radius 9 cm is melted and reformed into a wire of radius 1 mm. What will be the length of this wire? (Take π = 22/7)

Solution:

Radius of sphere = R = 9cm
Let length of wire = hcm and radius of wire = r= 0.1cm
Volume of sphere = Volume of wire
⇒

4/3π(R)^3=π(r)^2h

⇒

4/3×(9)^3=(0.1)^2h

⇒

h=12×81×100

cm
⇒

h={972×100}/100=972

metres

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