SSC CHSL 9 Jan 2017 Shift 1 Paper

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Question : 68 of 100

Marks: +1, -0

If

xy = 22

and

x^2+y^2

= 100, then what will be the value of

(x + y)

?

12
144
72
6

Solution:

Given :

x^2+y^2

= 100 and

xy = 22

Using

(x + y)^2 = x^2 + y^2 + 2xy

⇒

(x + y)^2 = 100 + (2 × 22)

⇒

(x + y) = √144 = 12

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