SSC CHSL Model Paper 10

Question : 62 of 100

Marks: +1, -0

Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

Solution:

Let the number be x.
Then,

x + 17 = 60/x

x^2 + 17x - 60 = 0

(x + 20)(x - 3) = 0

x = 3

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