SSC CHSL Model Paper 13

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Question : 67 of 100

Marks: +1, -0

If

\tanθ=3/4,

then

{4\sinθ-\cosθ}/{4\sinθ+\cosθ}

is equal to:

$1/4$
$3/5$
$2/5$
$1/2$

Solution:

\tanθ=3/4,

{4\sinθ-\cosθ}/{4\sinθ+\cosθ}

={{4\sinθ}/{\cosθ}-{\cosθ}/{\cosθ}}/{{4\sinθ}/{\cosθ}+{\cosθ}/{\cosθ}}

={4\tanθ-1}/{4\tanθ+1}

={4×3/4-1}/{4×3/4+1}=1/2

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