SSC CHSL Model Paper 14

In triangle ABD and ADC,
BD = DC (AD is the median)
AB = AC (Given)
Angle ABD = Angle ACD = 35° (Angles opposite equal sides are equal)
Since, Triangle ABD and Triangle ADC are congruent
Angle BAD = Angle CAD = x
Now in triangle ABC,
Angle ABD + Angle BAD + Angle DAC + AngleBCA= 180
35 + 35 + x + x = 180
2x = 110
x = 55°
Hence, angle BAD = 55°