Find the value of (\frac{\sin 27^\circ}{\cos63^\circ})^2+(\frac{\cos63^\circ}{\sin 27^\circ})^2:

SSC CHSL Model Paper 15

Question : 65 of 100

Marks: +1, -0

Find the value of

({\sin 27°}/{\cos63°})^2+({\cos63°}/{\sin 27°})^2:

Solution:

sin 27° = sin (90° - 63°) = cos 63°
[∵ sin (90° - θ) = cos θ]

∴({\sin 27°}/{\cos63°})^2+({\cos63°}/{\sin 27°})^2

({\sin 27°}/{\sin 27°})^2+({\sin 27°}/{\sin 27°})^2

= 1+1=2

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