SSC CHSL Model Paper 16

Question : 52 of 100

Marks: +1, -0

p(x) = x^2 - (2 + k)x + 2k

. At

x = 3, p(3) = 0

, then the value of k is

Solution:

x^ - (2 + k)x + 2k = p(x)

9 - (2 + k) 3 + 2k = p(3) = 0

then k = 3

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