SSC CHSL Model Paper 16

Question : 69 of 100

Marks: +1, -0

The angle of elevation of the top of a building from the foot of a tower is 30 degrees and the angle of elevation of the height of the tower from the foot of the building is 60 degrees. If the height of the tower is 60 m, the height of the building is

${50√3} / 3$ m
20 m
$50√3$ m
None of these

Validate

Solution:

Let AB and CD be tower and building
In ΔABC, tan 60 =

\AB/\BC

\BC=60/√3 \m

In ΔBCD, tan 30

=\CD/\BC

CD = 20m

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