SSC CHSL Model Paper 16

Question : 71 of 100

Marks: +1, -0

In the given figure ABCD is a cyclic quadrilateral and O is the centre of the circle. If ∠BOC = 138°, then ∠BDC will be

112°
111°
109°
None of these

Solution:

Draw the chord BC,

∠BAC = 1/2×1 3 8 ° = 6 9 °

(Angle subtended by the chord at the center is half the anglesubtended at the center)
So ∠BDC = 180° - 69° = 111° (Sum of opposite angles of a cyclic quadrilateral is 180°)

Go to Question:

Prev Question

Next Question