SSC CHSL Model Paper 18

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Question : 54 of 100

Marks: +1, -0

The H.C.F. of

(a^2 + 7a + 12)

and

(a^2 + 8a +15)

is

(a + 1) (a + 3)
(a + 2) (a + 3)
(a + 4) (a + 3)
(a + 3)

Solution:

Factorizing the given equations:

a^2 + 7a + 12 = (a + 4)(a + 3)

a^2 + 8a + 15 = (a + 5)(a + 3)

Thus, HCF = (a + 3)

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