SSC CHSL Model Paper 18

Question : 68 of 100

Marks: +1, -0

The line of x + 2y = 3 and 3x - 2y = 1 meet the y-axis at two points having distance of

Solution:

On Y axis, x = 0
Putting X = 0 in x + 2y = 3

2y = 3, y =3/2

Putting x = 0 in 3x - 2y = 1

- 2y = 1, y = - 1/2

points on Y axis are

(0,3/2)

and

(0,-1/2)

Required distance =

√{0+(3/2+1/2)^2}

=√{0+4}=2

units

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