SSC CHSL Model Paper 20

Question : 67 of 100

Marks: +1, -0

The external bisector of angle B of triangle ABC and line parallel to BC through point A, intersect at point D. If angle ABC = 50° then angle ADB is equal to

120°
115°
65°
None of these

Validate

Solution:

Angle BAD = Angle ABC = 50°
Angle ABD

={180-50}/2=65°

Angle ADB = 180 - 50 - 65 = 65°

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