If ( x–a )= 1 /{(x–b)}and a = b – 4, then (x–a )^3– 1/{(x–a)^3} = ?

SSC CPO SI and ASI Model Paper 3

Question : 116 of 200

Marks: +1, -0

( x–a )= 1 /{(x–b)}

and a = b – 4, then

(x–a )^3– 1/{(x–a)^3} = ?

Solution:

(x–a )^3– 1/{(x–a)^3}=

[(x–a )– 1/ (x–a)]^3

3( x–a) 1/{(x–a)}

[(x–a )– 1/{(x–a)}]

= [ x–a–x+b]^3 +3 [x–a–x+b]

=[b–a ]^3+3[b-a]

Given: a = b – 4 ⇔ b – a = 4

∴ [b–a ]^3+3[b-a]

= [4 ]^3+3[4]

= 64 + 12 = 76

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