SSC JE Civil Engineering 2014 Set 2 Solved Paper

Question : 112 of 200

Marks: +1, -0

Strain energy due to sudden axial load is given by :
σ : resultant stress
P : Axial load
Δ : detornator
∈ : strain
E : modulous of elasticity

$1/2$ PΔ
σ.∈
PΔ
$σ^2/{2E}$

Validate

Solution:

Strain energy due to gradually applied axial load is given by

U=1/2P\Δ

Now axial deformation due to sudden applied axial load is twice the axial deformation due to gradually applied axial load.
Hence, Strain energy due to suddenly applied axial load will be

U=1/2P(2\Δ)=P\Δ

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