SSC JE Civil Engineering 2014 Set 2 Solved Paper

Question : 128 of 200

Marks: +1, -0

When R is the radius of the curve (in meters), D is the degree of curve (in degrees) and length of the chord is 30m, then the relation between R and D is :

$R = 5400/D$
$R = 1520/D$
$R = 1720/D$
$R = 4500/D$

Validate

Solution:

Radius of curve (R) and degree of curve (D)

D°/360=1/{2πr}

● For 30 m chain length (l = 30 m)
Degree of curve, D°

={30×360}/{2πR}=1718.9/R

Radius of curve, R

={30×360}/{2πD°}=1718.9/D°

● For 20 m chain length (l = 20 m)
D°

={20×360}/{2πR}=1145.9/R

={20×360}/{2πD°}=1145.9/D°

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