SSC JE Electrical Engineering 2012 Paper

Question : 102 of 200

Marks: +1, -0

In a 1-phase transformer, the copper loss at full load is 600 Watts. At half of the full load the copper loss will be

Solution:

(P_\cu)_{\full \load }

= 600 watts

(P_\cu)_{\half \load}

600/4

=150 watts

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