SSC JE Electrical Engineering 2012 Paper

Question : 104 of 200

Marks: +1, -0

In an auto-transformer, the number of turns in primary winding is 210 and in secondary winding is 140. If the input current is 60A, the currents in output and in common winding are respectively

40 A, 20 A
40 A, 100 A
90 A, 30 A
90 A, 150 A

Validate

Solution:

I_\input/I_\output=N_2/N_1

⇒60/I_\output=140/210

⇒I_\output=90A

I_{\common \winding}={N_2-N_1}/N_2I_\output

={210-140}/140×60=30A

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