SSC JE Electrical Engineering 2014 Set 1 Paper

Question : 104 of 200

Marks: +1, -0

Calculate the voltage drop across 14.5 Ω resistance.

Solution:

I = 200/{14.5+25.5+60}=2A

Voltage drop across 14.5 Ω resistance = 14.5 × 2 = 29 V

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