SSC JE Electrical Engineering 2014 Set 1 Paper

Question : 149 of 200

Marks: +1, -0

The multiplying power of the shunt of a milliammeter is 8. If the circuit current is 200 mA, then current through the meter is

Solution:

Multiplying Power 'm' = 8
=

{\Circuit \current}/{\Full \scale \current \of \meter}

∞= {200mA}/I_{FL}

I_{FL}=25mA

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