SSC JE Electrical Engineering 2014 Set 1 Paper

Question : 175 of 200

Marks: +1, -0

The leakage resistance of a 50 km long cable is 1 MΩ . For a 100 km long cable it will be

Solution:

Leakage Resistance is inversely Proportional to the length therefore

R∝ 1/ L

R_1/R_2=L_1/L_2

R= {1×50}/100=0.5

mol

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