SSC JE Electrical Engineering 2014 Set 2 Paper

Question : 101 of 200

Marks: +1, -0

A lamp having mean spherical candle power of 800 is suspended at a height of 10 m. Calculate the illumination just below the lamp.

Solution:

Total flux = Mean Spherical Candle Power (MSCP)

× 4 π

= 800 × 4 π

Lumen intensity =

{\Total \flux}/{4π}={80×4π}/{4π}

= 800 CP

\Illuminaion = {\Lumen \intensity }/d^2

' α'

-height of lane from surface =

80/(10)^2=

0.8 Lax

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