SSC JE Electrical Engineering 2014 Set 2 Paper

Question : 153 of 200

Marks: +1, -0

A 2 cm long coil has 10 turns and carries a current of 750 mA. The magnetising force of the coil is :

Solution:

Magnetizing force (H)

={ NI}/l={10 ×750 ×10^{-3}} /{2× 10 ^{-2} }= 375 AT\/m

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