SSC JE Electrical Engineering 2014 Set 2 Paper

Question : 189 of 200

Marks: +1, -0

Using Millman's theorem, find the current through the load resistance

R_L

of 3 Ω resistance shown below :

Solution:

According to Millman's theorem

E_{\eq}={∑E_i Y_1}/∑Y_i

Y_1=1/3,Y_2=1/3,Y_3=1/3

L_{\eq}={8×1/3+96×1/3 +24×1/3}/{1/3×1/3×1/3}

=48/3V=16V

Y_{\eq}=Z_{\eq}=1/∑Y_i

=1/(1/3+1/3+1/3)=1

I= 16/ 4= 4 A

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